The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation class, a high school preparation class, and no preparation class. Use the information from the table to answer the remaining questions.&nbsp;TreatmentNumber of ObservationsSample MeanSum of Squares (SS)Private prep class60680265,500.00High school prep class60650276,120.00No prep class60635302,670.00&nbsp;Using the data provided, complete the partial ANOVA summary table that follows (Hint: T, the treatment total, can be calculated as the sample mean times the number of observations G, the grand total, can be calculated from the values of T once you have calculated them.)&nbsp;SourceSum of Squares (SS)dfMean Square (MS)Between treatments&nbsp;&nbsp;&nbsp;Within treatments&nbsp;&nbsp;&nbsp;&nbsp;ANOVA summary tables typically have a "Total" row not induded in the partial table you just completed. Which of the following is a possible reason for induding this row?&nbsp;a) The&nbsp;MS→tal&nbsp;is used in the calculation of the F test statistic.&nbsp;b) The&nbsp;SS→tal&nbsp;is used in the calculation of the F test statistic.&nbsp;c) The total sums of squares is the sometimes called the "error term"&nbsp;d) The&nbsp;SStotal&nbsp;is sometimes easier to calculate than.&nbsp;SSbetween&nbsp;Since&nbsp;SSwithin+SSbetween=SStotal, you can use&nbsp;SStotal&nbsp;to calculate&nbsp;SSbetween.In ANOVA, the F test statistic is the ? of the between-treatments variance and the within-treatments variance. the value of the F test statistic is ?&nbsp;When the null hypothesis is true, the F test statistic is ? When the null hypotesis is false, the F test statistic is most likely ? In general, you should reject the null hypotesis for.

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The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation class, a high school preparation class, and no preparation class. Use the information from the table to answer the remaining questions.&amp;nbsp;TreatmentNumber of ObservationsSample MeanSum of Squares (SS)Private prep class60680265,500.00High school prep class60650276,120.00No prep class60635302,670.00&amp;nbsp;Using the data provided, complete the partial ANOVA summary table that follows (Hint: T, the treatment total, can be calculated as the sample mean times the number of observations G, the grand total, can be calculated from the values of T once you have calculated them.)&amp;nbsp;SourceSum of Squares (SS)dfMean Square (MS)Between treatments&amp;nbsp;&amp;nbsp;&amp;nbsp;Within treatments&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;ANOVA summary tables typically have a &quot;Total&quot; row not induded in the partial table you just completed. Which of the following is a possible reason for induding this row?&amp;nbsp;a) The&amp;nbsp;MS→tal&amp;nbsp;is used in the calculation of the F test statistic.&amp;nbsp;b) The&amp;nbsp;SS→tal&amp;nbsp;is used in the calculation of the F test statistic.&amp;nbsp;c) The total sums of squares is the sometimes called the &quot;error term&quot;&amp;nbsp;d) The&amp;nbsp;SStotal&amp;nbsp;is sometimes easier to calculate than.&amp;nbsp;SSbetween&amp;nbsp;Since&amp;nbsp;SSwithin+SSbetween=SStotal, you can use&amp;nbsp;SStotal&amp;nbsp;to calculate&amp;nbsp;SSbetween.In ANOVA, the F test statistic is the ? of the between-treatments variance and the within-treatments variance. the value of the F test statistic is ?&amp;nbsp;When the null hypothesis is true, the F test statistic is ? When the null hypotesis is false, the F test statistic is most likely ? In general, you should reject the null hypotesis for.

faldduE · Accepted Answer

Step 1&amp;nbsp;Let&amp;nbsp;X1&amp;nbsp;be the SAT scores of students in a private preparation class.&amp;nbsp;Let&amp;nbsp;X2&amp;nbsp;be the SAT scores of students in a high school preparation class.&amp;nbsp;Let&amp;nbsp;X3&amp;nbsp;be the SAT scores of SAT scores of students in no preparation class.&amp;nbsp;From the available information,&amp;nbsp;n1=60,&amp;nbsp;x1―=680,&amp;nbsp;SS1=265500&amp;nbsp;n2=60,&amp;nbsp;x2―=650,&amp;nbsp;SS2=276120&amp;nbsp;n3=60,&amp;nbsp;x3―=635.&amp;nbsp;SS3=302670&amp;nbsp;Size of each group/treatment,&amp;nbsp;n=n1=60&amp;nbsp;Number of treatments,&amp;nbsp;k=3&amp;nbsp;x――=1k∑i=1kxi―=13{x1―+x2―+x3―}=13{680+650+635}=655&amp;nbsp;Between sum of squares,&amp;nbsp;SSbetween=∑i=1kn1(xi―−x――)2=n1(x1―−x――)2+n2(x2―−x――)2+n3(x3―−x――)2&amp;nbsp;=(60)(680−655)2+(60)(650−655)2+(60)(635−655)2&amp;nbsp;=63000&amp;nbsp;Within sum of squares,&amp;nbsp;SSwith∈=∑i=1kSS1+SS2+SS3&amp;nbsp;=265500+276120+302670&amp;nbsp;=844290&amp;nbsp;Degrees of freedom:&amp;nbsp;dfbetween=k−1=3−1=2&amp;nbsp;&amp;nbsp;

The following table summarizes the results of a study on SAT prep courses, compa

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