Algebraic Modeling subject\begin{array}{|c|c|}\hline x & -3 & -2 & -1

Carol Gates

Carol Gates

Answered question

2021-10-25

Algebraic Modeling subject
x32101234y427494341236108324
What is the exponential regression of the data?
y=?

Answer & Explanation

lamanocornudaW

lamanocornudaW

Skilled2021-10-26Added 85 answers

Step 1
Given a dataset where an exponential function y=abx where a and b are constants. are to be obtained.
Taking logarithm on both sides of the above equation,
log y=log a+xlog b
υ=A+Bx
where υ=log y
A=log a
B=log b
Hence, the exponential function is reduced to a linear function between υ and x and can be solved by least square method.
By principle of least squares, the normal equations for estimating A and B is given by,
υ=nA+Bx
υx=Ax+Bx2
Step 2
The following is table is formed to calculate the value of A and B
yxυ=log yx2υ42730.829392.48794920.352240.70444310.124910.1249400.6021001211.079211.07923621.556343.112610832.033496.100232442.51051610.0420Total46.72494423.4014
Hence, putting the values obtained from the table to the normal equations we get,
1) 6.7249=8A+4B
2) 23.4014=4A+44B
On solving the simultaneous equations, by method of comparison, it is obtained that,
from (1)
3) A=6.7249aB8
from (2)
4) A=23.401455B4
Comparing (3) and (4)
6.72494B8=23.401444B4
Hence solving the above equation, it is obtained that,
B=0.4771
b=Antilog B
=2.9999
Then putting the value of B in (3), it is obtained that,
A=0.6021
a=Antilog A
=4.0004
Therefore, the required exponential regression of the data is
y=4.0005(2.9999)x

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