To find: Here we are given the probability distribution of Male Color Blindness as, xP(x)00.65910.28720.05030.00440.00150+

Step 1 Note that by the property of probability distribution, P(0)+P(1)+P(2)+P(3)+P(4)+P(5)=1 But P(0)+P(1)+P(2)+P(3)+P(4)=1.001&gt;1 which is a contradiction and P(5)=1−(P(0)+P(1)+P(2)+P(3)+P(4))=1−1.001=−0.001&lt;0 which not possible. So, in this problem we are not given the probability distribution. Hence, we can’t calculate mean and standard deviation.

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ka1leE

Answered question

2021-10-16

To find:
Here we are given the probability distribution of Male Color Blindness as,
$\begin{array}{cc} x & P (x) \\ 0 & 0.659 \\ 1 & 0.287 \\ 2 & 0.050 \\ 3 & 0.004 \\ 4 & 0.001 \\ 5 & 0 + \end{array}$

Answer & Explanation

d2saint0

Skilled2021-10-17Added 89 answers

Step 1
Note that by the property of probability distribution,
$P (0) + P (1) + P (2) + P (3) + P (4) + P (5) = 1$
But $P (0) + P (1) + P (2) + P (3) + P (4) = 1.001 > 1$ which is a contradiction and
$P (5) = 1 - (P (0) + P (1) + P (2) + P (3) + P (4)) = 1 - 1.001 = - 0.001 < 0$ which not possible.
So, in this problem we are not given the probability distribution. Hence, we can’t calculate mean and standard deviation.

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