# Laplace transform of sin(2t)+e^{t}sin(t)

Rui Baldwin 2021-01-23 Answered
Laplace transform of $\mathrm{sin}\left(2t\right)+{e}^{t}\mathrm{sin}\left(t\right)$
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$\text{Step 1}$

$\text{Step 2}$

$L\left\{f\left(t\right)\right\}=L\left\{\mathrm{sin}\left(2t\right)+{e}^{t}\mathrm{sin}\left(t\right)\right\}$
$=L\left\{\mathrm{sin}\left(2t\right)\right\}+L\left\{{e}^{t}\mathrm{sin}\left(t\right)\right\}$

$=\frac{2}{{2}^{2}+4}+\frac{1}{{s}^{2}-2s+2}$
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