Evaluate the integrals. \int_0^2(2x+1)^3dx

Jaden Easton

Jaden Easton

Answered question

2021-10-27

Evaluate the integrals.
02(2x+1)3dx

Answer & Explanation

Luvottoq

Luvottoq

Skilled2021-10-28Added 95 answers

The given integral is 02(2x+1)3dx
Evaluate as follows.
02(2x+1)3dx=[12(2x+1)44]02
=18[(2(2)+1)4(2(0)+1)4]
=18(541)
=18(6251)
=6248
=78
Thus, 02(2x+1)3dx=78

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