GMU uses a robot food delivery service which now has been utilized in the City o

Step 1
Hypothesis Testing:
It is basically a comparison of the statistical measures of the data with one sample(population) or two samples(populations) or more than two samples(populations). There are two hypotheses namely NULL and ALTERNATIVE.
The tail of the hypothesis will be decided from the alternative hypothesis. If it is '<' then left tail; '>' then right tail; $\text{Undefined control sequence displaystylenene}$ then two-tail. Whereas the null hypothesis is almost '${\displaystyle =0}$' in most of the cases.
One-Sample Z-Test:
It is the hypothesis testing done for comparing the mean of the data to a specific value. As the name says it is a one-sample z-test, the data of one sample is considered for the complete hypothesis testing and the test statistics will be found from that data.
Step 2
Here, the level of significance is ${\displaystyle \alpha =0.05}$, The hypothesis statement is
${\displaystyle H_0:\hat{p}=Pvs{H}_1:\hat{p}<P}$
Now, before calculating the test statistics, the standard deviation of the population is calculated using the given population proportion.
Here, the proportion of the sample is,
${\displaystyle \hat{p}=\frac{453}{595}=0.761344538\stackrel{\sim }{=}0.7613}$
The standard deviation of the population using the population proportion is,
${\displaystyle \sigma =\sqrt{\frac{P\times (1-P)}{n}}}$
${\displaystyle =\sqrt{\frac{0.80\times (1-0.80)}{50}}}$
${\displaystyle =\sqrt{\frac{0.80\times 0.20}{50}}}$
${\displaystyle =\sqrt{\frac{0.16}{50}}}$
${\displaystyle =\sqrt{0.0032}}$
${\displaystyle =0.056568542}$
${\displaystyle \stackrel{\sim }{=}0.0566}$
Step 3
The test statistics is,
${\displaystyle Z=\frac{\hat{p}-P}{\sigma }}$
${\displaystyle =\frac{0.7613-0.80}{0.0566}}$
${\displaystyle =\frac{-0.0389}{0.0566}}$
${\displaystyle =-0.683745583}$
Now, the p-value is calculated by the normal distribution for the probability of the Z-score is less than -0.683745583.
That is,
${\displaystyle P(Z<-0.683745583)=0.24707}$
Therefore the p-value for the test statistics is approximately 0.24707.
Step 4
Conclusion:
As the p-value of the hypothesis test statistics is greater than 0.05, that is the level of significance of the test; there is no sufficient evidence to reject the null hypothesis. So, the GMU students who are all using the food delivery robots skip breakfast is ${\displaystyle 80\mathrm{\%}}$.