Given

\(\begin{array}{c|cc|c} &\text{Male}&\text{Female}&\text{Total}\\ \hline \text{Blue}&&&10\\ \text{Brown}&&&40\\ \hline \text{Total}&20&30&50 \end{array}\)

A=Male B=Blue eyes

Two events are disjoint or mutually exclusive, if the events cannot occur at the same time.

In this case, events A and B are mutually exclusive, which then implies that there are no males with blue eyes and thus we need to enter 0 in the row Blue” and in the column ”Male” of the given table.

The remaining counts can then be determined using the row/column totals

\(\begin{array}{c|cc|c} &\text{Male}&\text{Female}&\text{Total}\\ \hline \text{Blue}&0&10-0=10&10\\ \text{Brown}&20-0=20&30-10=20&40\\ \hline \text{Total}&20&30&50 \end{array}\)

Result:

\(\begin{array}{c|cc|c} &\text{Male}&\text{Female}&\text{Total}\\ \hline \text{Blue}&0&10&10\\ \text{Brown}&20&20&40\\ \hline \text{Total}&20&30&50 \end{array}\)