 # A random sample of 88 U.S. 11th- and 12th-graders was selected. The two-way table summarizes the gender of the students and their response to the question "Do you have allergies?" e1s2kat26 2020-12-09 Answered

A random sample of 88 U.S. 11th- and 12th-graders was selected. The two-way table summarizes the gender of the students and their response to the question "Do you have allergies?" Suppose we choose a student from this group at random.

What is the probability that the student is female or has allergies?
$\left(a\right)\frac{19}{88}$
(b)$\frac{39}{88}$
(c)$\frac{58}{88}$
(d)$\frac{77}{88}$

You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it Aniqa O'Neill

DEFINITIONS
Complement rule

General addition rule for any two events:

SOLUTION

We note that the table contains information about 88 peoples (given in the bottom right corner of the table).
Moreover, 34 of the 88 people have allergies, becatise 34 is mentioned in the row Yes” and in the column *Total” of the table.
The probability is the number of favorable outcomes divided by the number of possible outcomes:
We note that 43 of the 88 people are female, becatise 43 is mentioned in the row * Total” and in the column *Female” of the given table.
We note that 19 of the 88 people are females and have allergies, because 19 is mentioned in the row ” Yes” and in the column *Female” of the given table.

$=\frac{34}{88}+\frac{43}{88}-\frac{19}{88}$
$=\frac{34+43-19}{88}$
$=\frac{58}{88}$
Result: $\left(c\right)\frac{58}{88}$