The length of a rectangle is 5 meters less than 3 times the width. The perimeter is 14 meters. Find the width.

The length of a rectangle is 55 meters less than 33 times the width. The perimeter is 14 meters. Find the width.
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Jeffrey Jordon
I think that you mean 5 and 3 Start by turning the words into equations. l = length w = width length = 3*width - 5 l = 3*w - 5 P = perimeter = 2(l+w) = 2l + 2w, which is a known equation for a rectangle. P = 14 is given 2l + 2w = 14 Substituting what we know l equals. 2(3w-5) + 2w = 14 Multiply by 2 to remove the parenthesis. 6w - 10 + 2w = 14 Collect terms 8w - 10 = 14 Add 10 to both sides 8w = 24 Divide both sides by 8 w = 3 = width Looking back, we see l = 3w - 5 = 3(3) - 5 = 9 - 5 = 4 = length Always check your work. In this case, if the width = 3 and the length = 4, is the perimeter 14? 2(3)+2(4) = 6 + 8 = 14. Yes it is. Remember to state the answer. The length=4 and the width=3.