Evaluate the integral. \int_{1}^{4}\frac{t^{2}+1}{\sqrt{t}}dt

Marvin Mccormick

Marvin Mccormick

Answered question

2021-10-12

Evaluate the integral.
14t2+1tdt

Answer & Explanation

saiyansruleA

saiyansruleA

Skilled2021-10-13Added 110 answers

Step 1
Consider the integrals:
14t2+1tdt
Step 2
To solve the given integrals:
14t2+1tdt=14t2tdt+141tdt
14t212dt+14t12dt
=[t32+132+1]14+[t12+112+1]14
=25[(4)52(1)52]+2[(4)12(1)12]
further solving it,
=25(251)+2(21)
=625+2
=62+105
=725
So, the value of integral is 725.

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