Physics One Dimentional Motion Question

2021-10-18
A flowerpot accidentally falls off the window of a condominium unit. Your unit is located below where the flowerpot had fallen. Your window measures to be 1.60 m tall, and the time it takes the flowerpot to move past your window is 0.150 s (from the top part to the bottom part of the window).

How high from the top of your window did the flowerpot fell off?

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Answered 2021-10-26 Author has 1864 answers

\(Y = Y_o + VY_ot + (\frac{1}{2})at^2\)

\(1.6 = 0 + V_i(0.150) + \frac{1}{2}(9.8)(0.150^2)\)

Do the algebra and solve for \(V_i\)

\(9.9316\) m/s = \(V_i\)

We can use the velocity squared equation to find the distance \(H\) the question asks for using this \(V_i\) we found. Here I do use the origin I established in the beginning.

\(V^2 = V_o^2 + 2a(Y - Y_o)\)

\((9.9316^2) = 0^2 + 2(9.8) (H - 0)\)

Do the algebra and solve for \(H\)

\(H = 5.03\) m

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