# Physics One Dimentional Motion Question

2021-10-18
A flowerpot accidentally falls off the window of a condominium unit. Your unit is located below where the flowerpot had fallen. Your window measures to be 1.60 m tall, and the time it takes the flowerpot to move past your window is 0.150 s (from the top part to the bottom part of the window).

How high from the top of your window did the flowerpot fell off?

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$$Y = Y_o + VY_ot + (\frac{1}{2})at^2$$

$$1.6 = 0 + V_i(0.150) + \frac{1}{2}(9.8)(0.150^2)$$

Do the algebra and solve for $$V_i$$

$$9.9316$$ m/s = $$V_i$$

We can use the velocity squared equation to find the distance $$H$$ the question asks for using this $$V_i$$ we found. Here I do use the origin I established in the beginning.

$$V^2 = V_o^2 + 2a(Y - Y_o)$$

$$(9.9316^2) = 0^2 + 2(9.8) (H - 0)$$

Do the algebra and solve for $$H$$

$$H = 5.03$$ m