1. Determine the observed frequencies and the chi-square subtotals:
2. Add all chi-square subtotals:
\(\displaystyle{x}^{{{2}}}={2.674}\)
Determine the critical value using table VII with \(df=c-1=6-1=5\).
\(\displaystyle{x}^{{{2}}}{0.05}={11.070}\)
If the test statistic \(x^{2}\) is more than the critical value, then reject the null hypothesis:
\(2.674<11.070 \Rightarrow\) Do not reject \(H_{0}\)
The U.S. Census Bureau compiles census data on educational attainment of Americans. From the document Current Population Reports
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Answered 2021-09-23
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