Pure acid is to be added to a 20% acid solution to obtain 28 L of a 40% acid solution. What amounts of each should be used?
Pure acid is to be added to a 20% acid solution to obtain 28 L of a 40% acid solution. What amounts of each should be used?
floymdiT
2021-10-04
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Expert Answer
Nicole Conner
Answered 2021-10-05
Author has 97 answers
Let x be the amount of pure acid to be added so that 28-x is the amount of 20% acid solution, both in L.
In terms of percentage, a pure acid corresponds to 100%. So, we write: 20% of 28-x L+100% of x L = 40% of 28 L
0.2(28-x)+1(x)=0.4(28)
Solve for x: 5.6-0.2x+x=11.2
5.6+0.8x=11.2
0.8x=5.6
x=7
So, we need 7 L of pure acid solution and 21 L of 20% acid solution.
In terms of percentage, a pure acid corresponds to 100%. So, we write: 20% of 28-x L+100% of x L = 40% of 28 L
0.2(28-x)+1(x)=0.4(28)
Solve for x: 5.6-0.2x+x=11.2
5.6+0.8x=11.2
0.8x=5.6
x=7
So, we need 7 L of pure acid solution and 21 L of 20% acid solution.
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