Analysis of a hydrate of iron(III) chloride revealed that in a 10.00-g sample of the hydrate,6.00 g is anhydrous iron(3) chloride and 4.00 g is water

Chardonnay Felix 2021-10-01 Answered
Analysis of a hydrate of iron(III) chloride revealed that in a 10.00-g sample of the hydrate, 6.00 g is anhydrous iron(III) chloride and 4.00 g is water. Determine the formula and name of the hydrate.

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Answered 2021-10-02 Author has 24636 answers
Mass of anhydrous FeCl3 in 10g sample = 6g
Mass of water in 10g sample = 4g
So, moles of FeCl3 = 6/162.2 = 0.0369 moles
And, moles of Water = 4/18 = 0.22 moles
Molar ratio FeCl3 : H2O = 0.0369 : 0.22
Dividing by 0.0369, = 1 : 6.02
So, 1 mole of FeCl3 corresponds to 6 moles of water
So, the formula of the hydrate is FeCl3.6H2O
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