Step by step solution to "Calculate the velocity of an object thrown straight..."

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Alyce Wilkinson

Answered question

2021-10-01

Calculate the velocity of an object thrown straight up with an initial velocity of 25 m/s at 1.0 seconds.

Answer & Explanation

Jozlyn

Skilled2021-10-02Added 85 answers

There is a kinematics equation that describes how final velocity, initial velocity, time, and acceleration are related to one another. Written in y-coordinates, it looks like $v y = v y_{0} + a t$

In this case the acceleration that the object feels is the gravitational acceleration which points downward and so the equation can be written as $v y = v y_{0} - g t$

Now we can just substitute in the initial velocity $v y_{0} = 25 m / s$ (notice that this is positive because it is thrown upward), the time t=1 s, and the gravitational acceleration $g = 9.8 m / s^{2}$ to get $v y = (25 (m / s)) - (9.8 (m / s^{2})) (1) = [25 - 9.8] m / s = 15.2 m / s$

So the velocity at 1.0 seconds is 15.2 m/s upward.

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