if an object accelerates from rest, with a constant acceleration of 5.4 m/s^2 what will its velocity be after 28 seconds

BolkowN

BolkowN

Answered question

2021-09-19

if an object accelerates from rest, with a constant acceleration of 5.4 m/s^2 what will its velocity be after 28 seconds

Answer & Explanation

gotovub

gotovub

Skilled2021-09-20Added 98 answers

Acceleration is defined by
a=Δv/Δt
where Δv is the change is velocity and Δt is the time period. So let's plug in what we know
5.4=(vfinal0)/28
Solving for the final velocity, we get
vfinal=5.428=151.2m/s

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