# Add or subtract as indicated \frac{2}{xz^3}-\frac{14}{xz^3}

$$\displaystyle{\frac{{{2}}}{{{x}{z}^{{3}}}}}-{\frac{{{14}}}{{{x}{z}^{{3}}}}}$$

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Alix Ortiz
Step 1
The given operation is subtraction of fractions.
Step 2
When the denominator of two fractions are same,
we can add or subtract the numerators directly and
keep the denominator same. That is,
$$\displaystyle{\frac{{{2}}}{{{x}{z}^{{3}}}}}-{\frac{{{14}}}{{{x}{z}^{{3}}}}}={\frac{{{2}-{14}}}{{{x}{z}^{{4}}}}}={\frac{{-{12}}}{{{x}{z}^{{4}}}}}$$
the answer is $$\displaystyle{\frac{{-{12}}}{{{x}{z}^{{4}}}}}$$