Determine the lowest common multiple (LCM) and the highest common factor (HCF) o

fortdefruitI 2021-10-03 Answered
Determine the lowest common multiple (LCM) and the highest common factor (HCF) of the following algebraic terms by using prime factors:
\(\displaystyle{22}{a}^{{{5}}}{b}^{{{3}}}{c}^{{{2}}};{2}{a}^{{{4}}}{b}^{{{4}}}{c}^{{{3}}};{4}{a}^{{{2}}}{b}^{{{2}}}{c}^{{{5}}}\)

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Expert Answer

liannemdh
Answered 2021-10-04 Author has 20566 answers
Step 1
Given ,
\(\displaystyle{X}={22}{a}^{{{5}}}{b}^{{{3}}}{c}^{{{2}}}\)
\(\displaystyle{Y}={2}{a}^{{{4}}}{b}^{{{4}}}{c}^{{{3}}}\)
\(\displaystyle{Z}={4}{a}^{{{2}}}{b}^{{{2}}}{c}^{{{5}}}\)
Step 2
\(\displaystyle{22}{a}^{{{5}}}{b}^{{{3}}}{c}^{{{2}}};{2}{a}^{{{4}}}{b}^{{{4}}}{c}^{{{3}}};{4}{a}^{{{2}}}{b}^{{{2}}}{c}^{{{5}}}\)
Let \(\displaystyle{x}={2}\times{11}\times{a}^{{{5}}}\times{b}^{{{3}}}\times{c}^{{{2}}}\)
\(\displaystyle{y}={2}\times{a}^{{{4}}}\times{b}^{{{4}}}\times{c}^{{{3}}}\)
\(\displaystyle{z}={2}\times{2}\times{a}^{{{2}}}\times{b}^{{{2}}}\times{c}^{{{5}}}\)
\(\displaystyle{L}{C}{M}={2}\times{11}\times{2}\times{a}^{{{5}}}\times{b}^{{{4}}}\times{c}^{{{5}}}\)
\(\displaystyle{L}{C}{M}={44}{a}^{{{5}}}{b}^{{{4}}}{c}^{{{5}}}\)
\(\displaystyle{H}{C}{F}={2}\times{a}^{{{2}}}\times{b}^{{{2}}}\times{c}^{{{2}}}\)
\(\displaystyle{H}{C}{F}={2}{a}^{{{2}}}{b}^{{{2}}}{c}^{{{2}}}\)
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