Evaluate the integral. \int_{0}^{w}e^{-2a|t|}dt

Daniaal Sanchez

Daniaal Sanchez

Answered question

2021-10-01

Evaluate the integral.
0we2a|t|dt

Answer & Explanation

hajavaF

hajavaF

Skilled2021-10-02Added 90 answers

Step 1
Given integral:
0we2a|t|dt
Step 2
Now,
|t|=t for all t0
So,
0we2a|t|dt=0we2atdt
Use the common integral: eaudu=eaua
0we2a|t|dt=0we2atdt
=[e2at2a]0w
=[e2aw2ae2a×02a]
=[e2aw2a+12a]
=12a[e2aw+1]

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