A food safety guideline is that the mercury in fish should be below 1 part per m

lwfrgin 2021-09-25 Answered

A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 95% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna​ sushi?
0.600.820.090.891.290.490.82
What is the confidence interval estimate of the population mean μ?
? p±<μ< ? p±

You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

casincal
Answered 2021-09-26 Author has 82 answers

Step 1
x(xx¯)(xx¯)20.60.114290.013061220.820.105710.011175510.090.624290.389732650.890.175710.030875511.290.575710.331446940.490.224290.050304080.820.105710.01117551Total50.83777143
Here n=7
Sampke mean =x=xn=0.714
Sample S.D.=s=1n1(xx)2=0.3737
Step 2
Confidence Level=95Significance Level=α=(10095)%=0.05Degrees of freedom=n1=71=6Critical value=t=2.447[using Excel=TINV(0.05, 6)]
Standard Error =sn=0.1412
Margin of Error (M.E) =tsn=0.3456
Lower Limit=x(M.E)=0.3687
Upper Limit=x+(M.E)=1.0599

Did you like this example?
Subscribe for all access

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

You might be interested in

asked 2020-12-27

Consider the next 1000 98% Cis for mu that a statistical consultant will obtain for various clients. Suppose the data sets on which the intervals are based are selected independently of one another. How many of these 1000 intervals do you expect to capture the corresponding value of μ? 
What is the probability that between 970 and 990 of these intervals conta the corresponding value of Y =the number among the 1000 intervals that contain What kind of random variable is Y) (Use the normal approximation to the binomial distribution)

asked 2021-01-10

The average zinc concentration recovered from a sample of measurements taken in 36 different locations in a river is found to be 2.6 grams per liter. Find the 95% confidence intervals for the mean zinc concentration in the river. Assume that the population standard deviation is 0.3 gram per liter. (Z0.025=1.96,Z0.005=2.575)

asked 2021-02-23
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bottle is determined. Let j: denote the average alcohol content for the population of all bottles of the brand under study. Suppose that the resulting 95% confidence intervals (7-8, 9.6)
(a) Would 2 90%% confidence interval calculated from this same sample have been narrower or wider than the glven interval? Explain your reasoning.
(b) Consider the following statement: There is 9 95% chance that Is between 7.8 and 9.6. Is this statement correct? Why or why not?
(c) Consider the following statement: We can be highly confident that 95% of al bottles ofthis type of cough syrup have an alcohol content that is between 7.8 and 9.6. Is this statement correct? Why or why not?
asked 2021-08-03
A simple random sample of 60 items resulted in a sample mean of 80. The population standard deviation is σ=15
a) Compute the 95% confidence interval for the population mean. Round your answers to one decimal place.
b) Assume that the same sample mean was obtained from a sample of 120 items. Provide a 95% confidence interval for the population mean. Round your answers to two decimal places.
c) What is the effect of a larger sample size on the interval estimate?
Larger sample provides a-Select your answer-largersmallerItem 5 margin of error.
asked 2020-11-12
Do teachers find their work rewarding and satisfying? The article presents the results of a survey of 399 primary school teachers and 264 senior teachers. Of the elementary school teachers, 223 said they were very satisfied with their jobs, whereas 127 of the high school teachers were very satisfied with their work. Estimate the difference between the proportion of all elementary school teachers who are satisfied and all high school teachers who are satisfied by calculating a 95%CI.(UsePelementaryPhigh school. Round your answers to four decimal places.)
asked 2022-03-21

Let X1,,Xn be a random sample from f(xθ)=θxθ1 for 0<x<1. Find a confidence interval for θ using as pivotal quantity a function of the maximum likelihood estimator for θ.

asked 2022-04-25
Probability vs Confidence
My notes on confidence give this question:
An investigator is interested in the amount of time internet users spend watching TV a week. He assumes σ=3.5 hours and samples n=50 users and takes the sample mean to estimate the population mean μ.
Since n=50 is large we know that Xμσn approximates the Standard Normal. So, with probability α=0.99, the maximum error of estimate is E=zα2×σn1.27 hours.
The investigator collects that data and obtain X=11.5 hours. Can he still assert with 99% probability that the error is at most 1.27 hours?
With the answer that:
No he cannot, because the probability describes the method/estimator, not the result. We say that "we conclude with 99% confidence that the error does not exceed 1.27 hours."
I am confused. What is this difference between probability and confidence? Is it related to confidence intervals? Is there an intuitive explanation for the difference?

New questions