Simply plug in \(x=5\) to the equation I found \(x=5\) by doing this: \((x-5)=0\),

\(x= 5 2(5)^{3}-4(4)^{2}-7(5)-10=0\)

If this is true then \(x-5\) is a factor.

They are not equal so \(x-5\) is not a factor.

\(x= 5 2(5)^{3}-4(4)^{2}-7(5)-10=0\)

If this is true then \(x-5\) is a factor.

They are not equal so \(x-5\) is not a factor.