a) Determine the probability that exactly 4 out of 10

Jason Farmer

Jason Farmer

Answered question

2021-09-30

a) Determine the probability that exactly 4 out of 10 randomly selected Americans own a dog.
b) Determine the probability that 4, or fewer, out of 10 randomly selected Americans own a dog.

Answer & Explanation

Ezra Herbert

Ezra Herbert

Skilled2021-10-01Added 99 answers

a) It is given that Veterinary Medical Association states that 36-37% of Americans own a dog and a sample of 10 Americans is chosen at random. So, the sample size (n) will be 10.
Consider that the random variable X represents the number of Americans who own a dog, from the sample of 10 Americans.
Success is when a randomly selected American owns a dog. Thus, the probability of a success (p) is,
p=P(owns a dog)
=36%
=0.36
The binomial probability that exactly 4 out of 10 randomly selected Americans own a dog is represented by P(X=4)=b(10,0.36,4).
Software procedure:
Step-by-step procedure to obtain the required probability using Ti-83 Plus calculator is:
Click on 2nd DISTR.
Select A: binom p df, then press ENTER.
Enter trials: 10,p:0.36, x value:4.
Press Enter.
The output shows the probability as 0.2424. Therefore,
P(X=4)=0.2424
The probability that exactly 4 out of 10 randomly selected Americans own a dog is 24.24%.
b) The binomial probability that 4 or fewer out of 10 randomly selected Americans own a dog is represented by P(X4)=b(10,0.36, fewer than 4).
Software procedure:
Step-by-step procedure to obtain the required probability using Ti-83 Plus calculator is:
Click on 2nd DISTR.
Select A: binomcdf, then press ENTER.
Enter trials: 10,p:0.36, x value:4.
Press Enter.
The output shows the probability as 0.7292.
P(X4)=0.7292
Therefore, the probability that 4 or fewer out of 10 randomly selected Americans own a dog is 72.9%.

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