Assume that when adults with smartphones are randomly selected, 54%

Step 1
Given:
Probability of using smartphone in meetings or classes ${\displaystyle =0.54}$
Number of selecting adult smartphone ${\displaystyle =12}$
We have to find probability of selecting fewer than 3 of them use their smartphones in meetings or classes.
Step 2
We can use binomial probability to find required probability.
Formula:
${\displaystyle P(X=x)=\frac{n!}{x!(n-x)!}\times p^x\times {(1-p)}^{n-x}}$
Step 3
Therefore,
${\displaystyle P\left(X<3\right)=P(X=2)+P(X=1)}$
${\displaystyle P\left(X<3\right)=}$
${\displaystyle P(X=2)=\frac{2!}{2!(12-2)!}\}\times {0.54}^2\times {(1-0.54)}^{12-2}}$
${\displaystyle +P(X=1)=\frac{1!}{1!(12-1)!}\times {0.54}^1\times {(1-0.54)}^{12-1}}$
${\displaystyle P\left(X<3\right)=0.0082+0.0013=0.0094}$