The defective state of the material in a certain factory as "49%" has been deter

naivlingr

naivlingr

Answered question

2021-09-25

The defective state of the material in a certain factory as "49%" has been determined. Also, the number of producing a piece of piece is 49. According to this
a) What is the characteristic that at most 2 of the 10 random materials are defective?
b) What is the failure of machines that are crushed in a material?

Answer & Explanation

pivonie8

pivonie8

Skilled2021-09-26Added 91 answers

Step 1
Given:
The defective state of the material in a certain factory as "49%"
Step 2
a) What is the characteristic that at most 2 of the 10 random materials are defective?
Apply the binomial probability formula:
P(X)=(nX)pX(1p)nX
The full binomial probability formula with the binomial coefficient is
P(X)=n!X!(nX)!pX(1p)nX
P (at most 2 of the 10 random materials are defective) =P(0)+P(1)+P(2)
Substituting in values for this problem, n=10,p=0.49,x=0,1,2
P(0)=10!0!(100)!0.490(10.49)100
P(0)=0.0011904
P(1)=0.0114374
P(2)=0.0494499
Therefore,
P (at most 2 of the 10 random materials are defective) =P(0)+P(1)+P(2)=0.0620
b) What is the failure of machines that are crushed in a material?
Given that a machine is manufactured using the 49 materials,
If 49 machines to be manufactured, failure of machines would be =490.49=24.01 or 24

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