Assume that a procedure yields a binomial distribution with n=6 trials and

Zoe Oneal

Zoe Oneal

Answered question

2021-09-28

Assume that a procedure yields a binomial distribution with n=6 trials and a probability of success of p=0.50. Use a binomial probability table to find the probability that the number of successes x is exactly 3.
Click on the icon to view the binomial probabilities table.
P(3)=0.257 (Round to three decimal places as needed.)

Answer & Explanation

Fatema Sutton

Fatema Sutton

Skilled2021-09-29Added 88 answers

Step 1 Introduction:
Binomial Distribution: Let 'X' be a discrete random variable is said to follow Binomial Distribution then the probability mass function (PMF) is given by
P(X=x)=(nx)px(1p)nx;x=0,1,...,n
Here n is Number of trails
x is number of successes in n trails
p is probability of success and
(1p)=q is probability of failure.
Step 2 Answer and explanation:
Given information, number of trails n=6
Probability of success p=0.5 and
Probability of failure q=(1p)=10.5
=0.5
By using the Binomial probability, we need to find the probability that the number of successes x is exactly 3
i.e., P(X=x)=P(X=3)
Then,
P(X=3)=(63)(0.5)3(10.5)63
=6!3!(63)!(0.5)3(0.5)3
=20(0.5)6
=20(0.015625)
=0.3125
Therefore, the probability that the number of successes x is exactly 3 is P(X=3)=0.313.

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