Assume that a procedure yields a binomial distribution with a trial repeated

Wierzycaz

Wierzycaz

Answered question

2021-09-16

Assume that a procedure yields a binomial distribution with a trial repeated n=5 times. Use some form of technology to find the probability distribution given the probability p=0.413 of success on a single trial. 
(Report answers accurate to 4 decimal places.) 
kP(X=k)0 1 2 3 4 5 

Answer & Explanation

delilnaT

delilnaT

Skilled2021-09-17Added 94 answers

Step 1 
The Binomial probability distribution is: 
P(X=x)=(nx)(p)x(1p)nx 
In the formula, n denotes the number of trails, p denotes probability of success, and x denotes the number of success. 
The sample size is 5, and probability of success is 0.413. 
Step 2 
The probabilities are obtained by using MINITAB as follows: 
- Create a cell x with values 0, 1, 2, 3, 4, 5. 
- Choose Calc > Probability Distributions > Binomial Distribution. 
- Choose Probability. 
- Enter Number of trials as 25 and Event probability as 0.67. 
- In Input Column, enter x. 
- Click OK. 
The output using the procedure is, 
Probability Density Function 
xP(X=k)00.06969310.24517320.34499630.24273240.08539050.012016 
From the output, the probability distribution is, 
kP(x=k)00.069710.245220.345030.242740.085450.0120

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