# To match: The binomial probability statement with its corresponding normal

To match: The binomial probability statement with its corresponding normal distribution probability statement (a)-(d) after a continuity correction.

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dieseisB
Here, the binomial random variable x is more than 109.
By using continuity correction, the value 0.5 is added to the value of 109.
That is, $$\displaystyle{c}={109}$$
$$\displaystyle{P}{\left({x}{>}{109}\right)}={P}{\left({x}{>}{109}+{0.5}\right)}$$
$$\displaystyle={P}{\left({x}{>}{109.5}\right)}$$
Thus, the binomial probability statement corresponding to the normal distribution probability statement is $$\displaystyle{P}{\left({x}{>}{109.5}\right)}$$.
Option (b), option (c) and option (d) are incorrect, because the binomial probability statement corresponding to the normal distribution probability statement is $$\displaystyle{P}{\left({x}{>}{109.5}\right)}$$
Conclusion:
Therefore, the correct option is (a).