The Cartesian coordinates of a point are given. a) (2,-2) b) (-1,\sqrt{3}) Find the polar coordinates (r,\theta) of the point, where r is greater than

Jason Farmer

Jason Farmer

Answered question

2021-06-05

The Cartesian coordinates of a point are given.
a) (2,2)
b) (1,3)
Find the polar coordinates (r,θ) of the point, where r is greater than 0 and 0 is less than or equal to θ, which is less than 2π
Find the polar coordinates (r,θ) of the point, where r is less than 0 and 0 is less than or equal to θ, which is less than 2π

Answer & Explanation

Mitchel Aguirre

Mitchel Aguirre

Skilled2021-06-06Added 94 answers

Consider the Cartesian coordinates be (x,y).
The polar coordinates (r,θ) is defined as,
r2=x2+y2
x=rcosθ
y=rsinθ
This implies that, tanθ=yx
a) The Cartesian coordinates be (2,2).
Calculate r and θ as follows:
r2=22+(2)2
=8
r=±22
tanθ=yx
=22
=1
Thus, the angle θ is 3π4,7π4 as the angle 0θ2π
The polar coordinates of (2,-2) are,
(22,7π4), where r>0
(22,3π4), where r<0
b) The Cartesian coordinates be (1,3).
Calculate r and θ as follows:
r2=(1)2+(3)2
=4
r=±2
tanθ=yx
=31
=3
Thus, the angle θ is 2π3,5π3 as the angle 0θ2π
The polar coordinates of (1,3) are,
(2,2π3), where r>0
(2,5π3), where r<0

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Linear algebra

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?