Solve the equation.

$\frac{5}{2x+3}+\frac{4}{2x-3}=\frac{14x+3}{4{x}^{2}-9}$

chillywilly12a
2021-10-01
Answered

Solve the equation.

$\frac{5}{2x+3}+\frac{4}{2x-3}=\frac{14x+3}{4{x}^{2}-9}$

You can still ask an expert for help

likvau

Answered 2021-10-02
Author has **75** answers

Step 1

We have solve the equation

$\frac{5}{2x+3}+\frac{4}{2x-3}=\frac{14x+3}{4{x}^{2}-9}$

Step 2

Here,

$\frac{5}{2x+3}+\frac{4}{2x-3}=\frac{14x+3}{4{x}^{2}-9}$

$\Rightarrow \frac{5(2x-3)+4(2x+3)}{(2x+3)(2x-3)}=\frac{14x+3}{4{x}^{2}-9}$

$\Rightarrow \frac{10x-15+8x+12}{{\left(2x\right)}^{2}-{\left(3\right)}^{2}}=\frac{14x+3}{4{x}^{2}-9}$

$\Rightarrow \frac{18x-3}{4{x}^{2}-9}=\frac{14x+3}{4{x}^{2}-9}$

$\Rightarrow 18x-3=14x+3$

$\Rightarrow 18x-14x=3+3$

$\Rightarrow 4x=6$

$\Rightarrow x=\frac{6}{4}=\frac{3}{2}$

$\Rightarrow x=\frac{3}{2}$

This is the required answer.

We have solve the equation

Step 2

Here,

This is the required answer.

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Equation 1 is 5x - 2y - 4z = 3

and

Equation 2 is 3x + 3y + 2z = -3.

Eliminate z by copying Equation 1, multiplying Equation 2 by 2, and then adding the equations.

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