First use the discriminant to determine whether the equation has two nonreal com

Dottie Parra

Dottie Parra

Answered question

2021-09-19

First use the discriminant to determine whether the equation has two nonreal complex solutions, one real solution with a multiplicity of two, or two real solutions. Then solve the equation.
2x2x+5=0

Answer & Explanation

rogreenhoxa8

rogreenhoxa8

Skilled2021-09-20Added 109 answers

Step 1
The given quadratic equation is,
2x2x+5=0
If a quadratic equation is in the form of ax2+bx+c=0,a0 then the discriminant of the equation is given as,
D=b24ac
Putting the values, we get
D=(1)2425
=1-40
=-39
D<0
When the discriminant is less than zero, then the equation has two non-real complex numbers.
Hence, the given equation has two non-real complex numbers.
Step 2
On solving the given equation, we get
x=b±D2a
=(1)±3922
=1±39i4
Therefore, the solutions of the given equation are (14+394i) and (14394i)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?