# Solve each equation. n^{2}+7n-44=0

Solve each equation.
${n}^{2}+7n-44=0$
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Step 1
Consider the provided equation,
${n}^{2}+7n-44=0$
Solve the provided equation.
We know that the provided equation is quadratic equation.
So, for solving the above equation we apply the quadratic formula.
${n}_{1,2}=\frac{-b±\sqrt{{b}^{2}-4ac}}{2a}$
Here a=1, b=7 and c=-44.
Step 2
So, put the above values in the above formula.
${n}_{1,2}=\frac{-7±\sqrt{{7}^{2}-4\cdot 1\cdot \left(-44\right)}}{2\cdot 1}$
${n}_{1,2}=\frac{-7±15}{2\cdot 1}$
${n}_{1}=\frac{-7+15}{2\cdot 1},{n}_{2}=\frac{-7-15}{2\cdot 1}$
n=4, n=-11
Hence, the solution the provided equation is n=4, n=−11.