Equation in slope intercept form. line f has an equation of y=-9/10x-7 line g in

Step 1
Given, line f has an equation of $y=-\frac{9}{10}x-7$
${\displaystyle \therefore }$ Slope of line f, ${\displaystyle m_1=-\left(\frac{9}{10}\right)}$
Step 2
Line g is perpendicular to line f
${\displaystyle \therefore }$ Slope of line g, ${\displaystyle m_2=-(-\frac{1}{\frac{9}{10}})=\frac{10}{9}}$
line g includes the point (-3,-5)
${\displaystyle \therefore }$ equation of line g:
$(y-(-5))=(\frac{10}{9})(x-(-3))$
${\displaystyle \Rightarrow (y+5)=\left(\frac{10}{9}\right)(x+3)}$