Obtain Laplace transforms for the function sin(t-pi) step (t−pi)

Obtain Laplace transforms for the function $$\displaystyle{\sin{{\left({t}−π\right)}}}$$ step $$\displaystyle{\left({t}−π\right)}$$

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Using the delay theorem, we know that $$\displaystyle{L}{\left\lbrace{g{{\left({t}\right)}}}{s}{t}{e}{p}{\left({t}-{c}\right)}\right\rbrace}={c}^{{-{c}{s}}}{L}{\left\lbrace{g{{\left({t}+{c}\right)}}}\right\rbrace}$$
Thus:
$$\displaystyle{L}{\left\lbrace{\sin{{\left({t}-\pi\right)}}}{s}{t}{e}{p}{\left({t}-\pi\right)}\right\rbrace}={e}^{{-\pi{s}}}{L}{\left\lbrace{\sin{{\left({t}+\pi-\pi\right)}}}\right\rbrace}={e}^{{-\pi{s}}}{L}{\left\lbrace{\sin{{t}}}\right\rbrace}={e}^{{-\pi{s}}}\frac{{1}}{{{s}^{{2}}+{1}}}=\frac{{{c}^{{-\pi{s}}}}}{{{s}^{{2}}+{1}}}$$