If x is a real number, for what values of x is the equation (3x-6)(x-2)^{-1}=3 true. F. all values of x G. some values of x H. no values of x l. impossible to determine

Question

If x is a real number, for what values of x is the equation

(3 x - 6) (x - 2)^{- 1} = 3

true.
F. all values of x G. some values of x H. no values of x l. impossible to determine

Answer 1

(3 x - 6) (x - 2)^{- 1} = 3

\frac{3 x - 6}{x - 2} = 3

3 x - 6 = 3 (x - 2)

3 x - 6 = 3 x - 6

Since this is true for all values of x with the exception of

x = 2^{1}

, so the answer choice is G.
Note:(1) if

x = 2

, we are dividing by 0, bit we cant

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