# Write the solutions or, if there is no solution, say the system is inconsistent.[ 1 0 -1 1 0 1 2 1 ]

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent. $$\begin{bmatrix}1 & 0 & -1 & | & 1 \\0 & 1 & 2 & | & 1 \end{bmatrix}$$

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Corben Pittman
There are no impossible equations, such as (0=1), the system is consistent,
A variable does not have a leading 1 in its corresponding column, so we take it asa parameter ... the system is consistent and has infinitely many solution.
Parameters: $$\displaystyle{x}{3}∈{R}$$
Interpreting row by row as equations.