Write the point-slope form of the line satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation. Slope=6, passing through (-5,4)

ka1leE
2021-09-25
Answered

Write the point-slope form of the line satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation. Slope=6, passing through (-5,4)

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Jaylen Fountain

Answered 2021-09-26
Author has **170** answers

Step 1

Given data is :

Slope m=6

Point$({x}_{1},{y}_{1})=(-5,4)$

The equation of line in point slope form is ,

$y-{y}_{1}=m(x-{x}_{1})$ ...(1)

Substitute the value of m and$({x}_{1},{y}_{1})$ in equation (1),

y-4=6[x-(-5)]

y-4=6(x+5)

Thus , the equation of line in point slope form is y−4=6(x+5)

Step 2

Equation of line in slope intercept form from point slope form

y-4=6(x+5)

y=6x+30+4

y=6x+34...(2)

Standard form of slope intercept form of the equation is,

y=mx+c

From standard equation of slope intercept form its clear that equation (2) represent slope intercept form.

Thus, Equation of line in slope intercept form is y=6x+34

Given data is :

Slope m=6

Point

The equation of line in point slope form is ,

Substitute the value of m and

y-4=6[x-(-5)]

y-4=6(x+5)

Thus , the equation of line in point slope form is y−4=6(x+5)

Step 2

Equation of line in slope intercept form from point slope form

y-4=6(x+5)

y=6x+30+4

y=6x+34...(2)

Standard form of slope intercept form of the equation is,

y=mx+c

From standard equation of slope intercept form its clear that equation (2) represent slope intercept form.

Thus, Equation of line in slope intercept form is y=6x+34

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