Write the​ point-slope form of the line satisfying the given conditions. Then us

Step 1
Given data is :
Slope m=6
Point ${\displaystyle (x_1,y_1)=(-5,4)}$
The equation of line in point slope form is ,
${\displaystyle y-y_1=m(x-x_1)}$...(1)
Substitute the value of m and ${\displaystyle (x_1,y_1)}$ in equation (1),
y-4=6[x-(-5)]
y-4=6(x+5)
Thus , the equation of line in point slope form is y−4=6(x+5)
Step 2
Equation of line in slope intercept form from point slope form
y-4=6(x+5)
y=6x+30+4
y=6x+34...(2)
Standard form of slope intercept form of the equation is,
y=mx+c
From standard equation of slope intercept form its clear that equation (2) represent slope intercept form.
Thus, Equation of line in slope intercept form is y=6x+34