# Write the​ point-slope form of the line satisfying the given conditions. Then us

Write the​ point-slope form of the line satisfying the given conditions. Then use the​ point-slope form of the equation to write the​ slope-intercept form of the equation. Slope​=6, passing through ​(-5​,4​)
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Step 1
Given data is :
Slope m=6
Point $\left({x}_{1},{y}_{1}\right)=\left(-5,4\right)$
The equation of line in point slope form is ,
$y-{y}_{1}=m\left(x-{x}_{1}\right)$...(1)
Substitute the value of m and $\left({x}_{1},{y}_{1}\right)$ in equation (1),
y-4=6[x-(-5)]
y-4=6(x+5)
Thus , the equation of line in point slope form is y−4=6(x+5)
Step 2
Equation of line in slope intercept form from point slope form
y-4=6(x+5)
y=6x+30+4
y=6x+34...(2)
Standard form of slope intercept form of the equation is,
y=mx+c
From standard equation of slope intercept form its clear that equation (2) represent slope intercept form.
Thus, Equation of line in slope intercept form is y=6x+34