To find the x-intercept(s), if any, of the graph of an equation, let in the equa

naivlingr

naivlingr

Answered question

2021-09-24

To find the x-intercept(s), if any, of the graph of an equation, let in the equation and solve for x.
(a) y = 0 (b) x = 0
(c) y = x (d) x = - y

Answer & Explanation

Liyana Mansell

Liyana Mansell

Skilled2021-09-25Added 97 answers

Step 1
The correct option is a.
Because, to find the x-intercepts, if any, of the graph of an equation, let y=0 in the equation and solve for x.
That is the point will be (x,y)=(x,0).
or
There is one other method to solve this.
For the point (0,0) to be on the graph of the equation y=x4x, x=0, y=0 must satisfy the equation.
Substitute 0 for both x and y.
y=x4x
0=040
0=0
Since, y=0, the point (0,0) satisfies the equation, (0,0) is a point on the graph of y=x4x.
Step 2
If the point (1,1) is on the graph of the equation y=x4x then x=1,y=1 must satisfy the equation.
Substitute 1 for both x and y.
y=x4x
1=1-1
10
Since, x=1,y=1 do not satisfy the equation, (1,1) is not a point on the graph of y=x4x.
If the point (−1,0) is on the graph of the equation y=x4x then x=−1,y=0 must satisfy the equation.
Substitute -1 for x and 0 for y.
y=x4x
0=(1)41
011
Since, x=−1,y=0 do not satisfy the equation, (−1,0) is not a point on the graph of y=x4x.
Therefore, (0,0) is a point on the graph of y=x4x.

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