Find the linear equation of the plane through the point (6,−2,5) and with normal

tabita57i

tabita57i

Answered question

2021-09-17

Find the linear equation of the plane through the point (6,−2,5) and with normal vector j+2k.

Answer & Explanation

Leonard Stokes

Leonard Stokes

Skilled2021-09-18Added 98 answers

Step 1
Given, point (6,-2,5) and normal vector j+2k
Step 2
Concept:
When point (x0,y0,z0) and normal vector ai+bj+ck, then equation of plane is given by a(xx0)+b(yy0)+c(zz0)=0
Step 3
Here, (x0,y0,z0)=(6,2,5) and a=0, b=1, c=2
Then, equation of plane is 0(x-6)+1(y-(-2))+2(z-5)=0
(y+2)+2z-10=0
Equation of plane y+2z-8=0
Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-27Added 2605 answers

Answer is given below (on video)

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