Find the laplace transform of the following f(t)=tu_2(t) Ans. F(s)=left(frac{1}{s^2}+frac{2}{s}right)e^{-2s}

Bevan Mcdonald 2020-10-31 Answered
Find the laplace transform of the following
f(t)=tu2(t)
Ans. F(s)=(1s2+2s)e2s
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Expert Answer

Theodore Schwartz
Answered 2020-11-01 Author has 99 answers

Step 1
first calculate Laplace transform of u2(t)
Fu(s)=u2(t)estdt
=2estdt
=e2ss
Step 2
therefore, Laplace transform of tu2(t) is :
ddsFu(s)=ddse2ss
=2se2se2ss2
=(1s2+2s)e2s
Therefore, Laplace transform of tu2(t) is
=(1s2+2s)e2s)

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