Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integers?

Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integers?
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Let x be the least of the three consecutive old integers.
Since consecutive old integers are 2 away from each other, the next two are $x+2$ and $x+4$.
Two times the least is then 2x and three times the gretaest is then $3\left(x+4\right)$.
2x exceeds $3\left(x+4\right)$ by 15 which means the difference of 2x and $3\left(x+4\right)$ is equal to 15.
$2x-3\left(x+4\right)=15$
Distribute the -3 to x and 4.
$2x-3\left(x\right)-3\left(4\right)=15$
$2x-3x-12=15$
Combine the like terms of 2x and -3x on the left side.
$-x-12=15$
$-x-12+12=15+12=x=27$
Multiply both sides by -1.
$-x\ast -1=27\ast -1$
$x=-27$
Find the order two old integers by substituing in $x=-27$ into $x+2$ and $x+4$.
$x+2=-27+2=-25$
$x+4=-27+4=-23$
Results: -27, -25, and -23