Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integers?

Lipossig 2021-02-09 Answered
Two times the least of three consecutive odd integers exceeds three times the greatest by 15. What are the integers?
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opsadnojD
Answered 2021-02-10 Author has 95 answers
Let x be the least of the three consecutive old integers.
Since consecutive old integers are 2 away from each other, the next two are x+2 and x+4.
Two times the least is then 2x and three times the gretaest is then 3(x+4).
2x exceeds 3(x+4) by 15 which means the difference of 2x and 3(x+4) is equal to 15.
2x3(x+4)=15
Distribute the -3 to x and 4.
2x3(x)3(4)=15
2x3x12=15
Combine the like terms of 2x and -3x on the left side.
x12=15
Add 12 on both sides.
x12+12=15+12=x=27
Multiply both sides by -1.
x1=271
x=27
Find the order two old integers by substituing in x=27 into x+2 and x+4.
x+2=27+2=25
x+4=27+4=23
Results: -27, -25, and -23
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