We assume that, for a given binary channel, 40% of the time a | is transmitted. the probability that a transmitted 0 is correctly received is 0.90

nicekikah

nicekikah

Answered question

2021-09-20

a simple binary communication channel carries messages by using only two signals, say 0 and 1. We assume that, for a given binary channel, 40% of the time a | is transmitted. the probability that a transmitted 0 is correctly received is 0.90 and the probability that a transmitted | is correctly received is 0.95. the probability of a 1 being received

Answer & Explanation

Mayme

Mayme

Skilled2021-09-21Added 103 answers

Let R be the event of signal that is correctly received.
The probability that the signal 1 is transmitted is P(1)=0.40.
The probability that the signal 0 is transmitted is P(0)=1-0.40=0.60.
The probability that the transmitted 0 is correctly received is P(R|0)=0.90.
The probability that a transmitted 1 is correctly received is P(R|1)=0.95.
(a) The probability of a 1 being received is given as:
P(R)=(P(1)×P(R|1))+(P(0)×P(R|0))
=(0.40×0.95)+(0.60×0.90)
=0.38+0.54
=0.92
Therefore, the probability of a 1 being received is 0.92.

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