Find \frac{dy}{dx} and \frac{d^2y}{dx^2}.x=e^t,y=te^{-t}. For which values of

mattgondek4 2021-09-11 Answered
Find \(\displaystyle{\frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}}\) and \(\displaystyle{\frac{{{d}^{{2}}{y}}}{{{\left.{d}{x}\right.}^{{2}}}}}.{x}={e}^{{t}},{y}={t}{e}^{{-{t}}}\). For which values of t is the curve concave upward?

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AGRFTr
Answered 2021-09-12 Author has 2989 answers
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