You randomly pick two cans, one at a time (without replacement).What is the probability that you do not get two cans of Coke?

a2linetagadaW

a2linetagadaW

Answered question

2021-09-13

A large cooler contains a total of 41 softdrinks, of which:
15 are lemonades,
6 are Sprites,
8 are Cokes, and
12 are root beers.
You randomly pick two cans, one at a time (without replacement).
What is the probability that you do not get two cans of Coke?

Answer & Explanation

Clara Reese

Clara Reese

Skilled2021-09-14Added 120 answers

The probability of getting one Coke is 8/41.
The probability of getting another Coke from remaining 40 cans is 7/40.
Selection of these two Coke are mutually exclusive.
Hence, the probability that of getting two cans of Coke is (8/41)(7/40) = 56/1,640 = 7/205.
Thus, the probability that of not getting two cans of Coke is, (1 – (7/205)) = 198/205.

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