Concept used:

If a straight line passes through the points (a, 0) (on the x-axis) and (0, b) (on the y-axis), we say that the x-intercept is a and the y-intercept is

b.

The x -intercept is found by setting \(\displaystyle{y}={0}\) and solving for a, similarly, the y-intercept is found by setting \(\displaystyle{x}={0}\) and solving for b.

Calculation:

For the given equation \(\displaystyle{4}{x}-{3}{y}={12}\)

\(\displaystyle{y}={0}\Rightarrow{4}{x}={12}\Rightarrow{x}-\text{intercept}={3},\)

\(\displaystyle{x}={0}\Rightarrow-{3}{y}={12}\Rightarrow{y}-\text{intercept}=-{4}\)

Conclusion:

For the given line, \(\displaystyle{x}-\text{intercept}={3}{\quad\text{and}\quad}{y}-\text{intercept}=-{4}\)

If a straight line passes through the points (a, 0) (on the x-axis) and (0, b) (on the y-axis), we say that the x-intercept is a and the y-intercept is

b.

The x -intercept is found by setting \(\displaystyle{y}={0}\) and solving for a, similarly, the y-intercept is found by setting \(\displaystyle{x}={0}\) and solving for b.

Calculation:

For the given equation \(\displaystyle{4}{x}-{3}{y}={12}\)

\(\displaystyle{y}={0}\Rightarrow{4}{x}={12}\Rightarrow{x}-\text{intercept}={3},\)

\(\displaystyle{x}={0}\Rightarrow-{3}{y}={12}\Rightarrow{y}-\text{intercept}=-{4}\)

Conclusion:

For the given line, \(\displaystyle{x}-\text{intercept}={3}{\quad\text{and}\quad}{y}-\text{intercept}=-{4}\)