# Math

Describe the error in solving the equation for x.

• In the third step, the left side was not divided by −2−2 correctly.

• In the third step, the negative sign was not distributed to both terms in parentheses.

• The equation is not solved for xx because there is still a term with xx on both sides.

• The equation cannot be solved for xx because the terms with xx cancel out on each side.

### Question 2

Correct the error.

x=

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$12-2x=-2\left(y-x\right)$

Simplify $-2\left(y-x\right)-2\left(y-x\right).$

Rewrite.

$12-2x=0+0-2\left(y-x\right)$

$12-2x=-2\left(y-x\right)$

Apply the distributive property.

$12-2x=-2y-2\left(-x\right)$

Multiply $-1$ by $-2$.

$12-2x=-2y+2x$

Move all terms containing x to the left side of the equation.

Subtract $2x$ from both sides of the equation.

$12-2x-2x=-2y$

Subtract 2x from −2x.

$12-4x=-2y$

Subtract $12$ from both sides of the equation.

$-4x=-2y-12$

Divide each term in $-4x=-2y-12$ by $-4$ and simplify.

$\frac{-4x}{4}=\frac{-2y}{-4}+\frac{-12}{-4}$

Simplify the left side.

$x=\frac{-2y}{-4}+\frac{-12}{-4}$

Simplify the right side.

$x=\frac{y}{2}+3$