a) Show that P(h0)=K(vf) b) Interpret result from part a) Given: N

Albarellak 2021-09-08 Answered
a) Show that P(h0)=K(vf)
b) Interpret result from part a)
Given:
A ball with mass m is dropped from an initial height of h0, and lands with a final velocity of vf. The kinetic energy of the ball is K(v)=12mv2, where v is its velocity and the potential energy of the ball is P(h)=mgh, where h is its height and g is a constant.
vf=2gh0
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Expert Answer

au4gsf
Answered 2021-09-09 Author has 95 answers
Calculation:
a) The kinetic energy of the ball at final velocity is
K(vf)=K(2gh0)
K(vf)=12m(2gh0)2
K(vf)=12m(2gh0)
K(vf)=mgh0
The potential energy at h0 is P(h0)=mgh0
Therefore P(h0)=K(vf)
b) The potential energy of the ball before it is dropped is equal to the kinetic energy of the ball when it lands.
Conclusion:
c) P(h0)=K(vf)
d) The potential energy of the ball before it is dropped is equal to the kinetic energy of the ball when it lands.
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