The solution of the system of equation using back substitution and writing the s

Zoe Oneal

Zoe Oneal

Answered question

2021-09-19

The solution of the system of equation using back substitution and writing the solution as ordered triple.
Given: The augmented matrix [1040120003413] is in row-echelon form and represents a linear system.

Answer & Explanation

oppturf

oppturf

Skilled2021-09-20Added 94 answers

Back substitution is the process of solving a linear system of equations that has beentransformed into row-echelon form or reduced row-echelon form. The last equation is solved first, then the next-to-last, etc.
The given augmented matrix represent a system of linear equation with 3 variable x,y and z. We obtain the following linear equation:
1x+0y4z=341st. Equation 0x+1y+2z=12nd. Equation 0x+0y+0z=33rd Equation
The last equation says 0=3 which is NOT TRUE, so there is NO SOLUTION for the given system of equation.
Calculation:
Description1x+0y4z=341stEquation0x+1y+2z=12ndEquation0x+0y+0z=33rdEquationStep 1: The last equation says 0=-30=3NOT TRUE, so there is NO SOLUTION for the given system of equation.
Conclusion:
The solution of the system of equation using back substitution is given by NO SOLUTION.

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