An electric utility company determines the monthly bill by charging 85.4 cents p

Question

An electric utility company determines the monthly bill by charging 85.4 cents p

Anonym 2021-09-18 Answered

An electric utility company determines the monthly bill by charging 85.4 cents per kilowatt-hour (kWh) used plus a base charge of $17.55 per month. Thus, the monthly charge is given by the function

f (W) = 0.854 W + 17.55

dollars, where W is the number of kilowatt-hours.
a. Find f (6000) and explain what it means.
b. What is the monthly charge if 9500 kWh are used?
a. Select the correct choice below and fill in the answer box to complete your choice.
(Simplify your answers. Type integers or decimals.)
A.

​ f (6000 ​) =

nothing.
The charge for 6000 kWh is $nothing.
B.

​ f (6000 ​) =

nothing.
The charge for nothing kWh is $6000.
b. The monthly charge is $nothing if 9500 kWh are used.
(Simplify your answer. Type an integer or a decimal.)

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Expert Answer

opsadnojD

Answered 2021-09-19 Author has 95 answers

Step 1
Given that
An electric utility company determines the monthly bill by charging 85.4 cents per kilowatt-hour (kWh) used plus a base charge of $17.55 per month. Thus, the monthly charge is given by the function

f (W) = 0.854 W + 17.55

dollars, where W is the number of kilowatt-hours.
Step 2
To find a. f(6000).
b. What is the monthly charge if 9500 kWh is used.
a. To find: f(6000).
The monthly charge is given by function,

f (W) = 0.854 W + 17.55

So to find f(6000) substitute

W = 6000 \in f (W) = 0.854 W + 17.55

,

\Rightarrow f (6000) = 0.854 (6000) + 17.55

\Rightarrow f (6000) = 5141.55

Therefore there is monthly charge of $5141.55 if 6000 kWh is used.
Step 3
b. To find What is the monthly charge if 9500 kWh is used.
Substitute

W = 9500 \in f (W) = 0.854 W + 17.55

,

f (9500) = 0.854 (9500) + 17.55

\Rightarrow f (9500) = 8130.55

Therefore the monthly charge if 9500 kWh is used is $8130.55.

This is helpful 96

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