Step 1

\(\displaystyle{t}=\) Amount of time submarine sise towards

\(\displaystyle{L}{\left({t}\right)}=\) sea level position of submarine

Total time sequired for submarine to sife @ \(\displaystyle=\frac{{560}}{{2.5}}{f}\frac{{t}}{{\sec{=}}}{224}{\sec{}}\).

\(\displaystyle\rightarrow\) depth at submarine @ particular time,

\(\displaystyle{L}{\left({t}\right)}=-{\left({t}\cdot{2.5}\right)}+{560}\) (total depth)

LInear approx. \(\displaystyle{L}{\left({t}\right)}={560}-{2.5}{t}\) (feet)

Step 2

Linear approximation for the second problem will be,

\(\displaystyle{L}{\left({t}\right)}={460}-{1.75}{t}\) ......................(Answer)

\(\displaystyle{t}=\) Amount of time submarine sise towards

\(\displaystyle{L}{\left({t}\right)}=\) sea level position of submarine

Total time sequired for submarine to sife @ \(\displaystyle=\frac{{560}}{{2.5}}{f}\frac{{t}}{{\sec{=}}}{224}{\sec{}}\).

\(\displaystyle\rightarrow\) depth at submarine @ particular time,

\(\displaystyle{L}{\left({t}\right)}=-{\left({t}\cdot{2.5}\right)}+{560}\) (total depth)

LInear approx. \(\displaystyle{L}{\left({t}\right)}={560}-{2.5}{t}\) (feet)

Step 2

Linear approximation for the second problem will be,

\(\displaystyle{L}{\left({t}\right)}={460}-{1.75}{t}\) ......................(Answer)