# Give all possible answers m\angle C=36^{\circ},\ AB=31,\ BC=24, find P

find $m\mathrm{\angle }A$
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Step 1
Given

By sine law,
$\frac{AB}{\mathrm{sin}C}=\frac{BC}{\mathrm{sin}A}$
$\frac{31}{{\mathrm{sin}36}^{\circ }}=\frac{24}{\mathrm{sin}A}$
$\mathrm{sin}A=\frac{24}{31}{\mathrm{sin}36}^{\circ }=0.45506$
$A=\mathrm{arcsin}\left(0.45506\right)$
$A={27}^{\circ }$
Answer: $A={27}^{\circ }$